cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且π/2cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且 π/2

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cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且π/2cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且 π/2
cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且π/2
cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且 π/2

cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且π/2cos(a-b/2)=-1/9 sin(a/2-b)=2/3 且 π/2
cos[(a+b)/2]=cos[(a-b/2)-(a/2-b)]
=cos(a-b/2)cos(a/2-b)+sin(a/2-b)sin(a-b/2)
cos(a-b/2)=-1/9,sin(a/2-b)=2/3
且π/2