​如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO

​如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO
​如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO
如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO

​如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO如图,AC,BD相交于点O,且AB=DC,AC=DB求证：∠ABO=∠DCO
证明:连接AD.
∵AB=DC,BD=AC(已知);
AD=DA.(公共边相等).
∴⊿BAD≌⊿CDA(SSS),∠ABO=∠DCO.