(1/x-3减x+1/x²-1)×(x-3)= A.2 B.2/x-1 C.2/x-3 D.x-4/x-1

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(1/x-3减x+1/x²-1)×(x-3)= A.2 B.2/x-1 C.2/x-3 D.x-4/x-1
(1/x-3减x+1/x²-1)×(x-3)= A.2 B.2/x-1 C.2/x-3 D.x-4/x-1

(1/x-3减x+1/x²-1)×(x-3)= A.2 B.2/x-1 C.2/x-3 D.x-4/x-1
(1/x-3减x+1/x²-1)×(x-3)
=1-(x-3)(x+1)/(x²-1)
=(x²-1-x²+2x+3)/(x²-1)
=(2x+2)/[(x-1)(x+1)]
=2/(x-1)
所以选B

原式=1/(x-3)x(x-3)-(x 1)/(x^2-1)x(x-3)
=1-(x-3)/(x-1)(x^2-1=(x-1)(x 1))
=(x-1-x 3)/(x-1)
=2/(x-1)选B