化简:cos(α-π/2)/sin(5π/2+α)乘以sin(α-2π)乘以cos(2π-α)

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化简:cos(α-π/2)/sin(5π/2+α)乘以sin(α-2π)乘以cos(2π-α)
化简:cos(α-π/2)/sin(5π/2+α)乘以sin(α-2π)乘以cos(2π-α)

化简:cos(α-π/2)/sin(5π/2+α)乘以sin(α-2π)乘以cos(2π-α)
cos(-π/2)/sin(5π/20+sin(α-2π)cos(2π-α)
=(sinα/cosα)(-sinα) cosα
=-sinα的平方

[sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简[tan(2π-α)sin(-2π-α)cos(6π-α)]/[cos(α-π)sin(5π-α)] 化简tan(2π-α)sin(-2π-α)cos(6π-α)/cos(α-π)sin(5π-α) 化简:[ cos(α-π/2)/sin(5π/2+α) ] ×sin(α-2π) × cos(2π-α)RT. 化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π 2sinα*cosα*cos(2π-α)+cos(π+2α)*cosα*tanα化简! 1.化简根号2cos x - 根号6sin x2.已知sin(α-β)cosα-cos(β-α)sinα=3/5,β是第三象限角,求sin(β+5π/4)的值.3.化简sin(α-β)sin(β-λ)-cos(α-β)cos(λ-β) 化简[sin(π/2-α)cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α) sin(α-β)sin(β-r)-cos(α-β)cos(r-β) 1.sin(α-β)sin(β-r)-cos(α-β)cos(r-β)2.( tan4分之5π+tan12分之5π)/(1-tan12分之5π)3.[ sin(α+β)-2sinαcosβ]/2sinαsinβ+cos(α+β) 已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α) 【三角函数】已知sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-α)] 化简:[sin( π -a) cos( π+a)cos(3/2 π+a )]/cos(3 π-a )sin(3 π+a )sin(5/2 π-a ) 已知α∈(π,2π) sinα+cosα=1/5 求sinα*cosα sinα-cosα 若sin(α-π)=2cos(2π-α),求(sinα+5cosα)/(sinα-3cosα)的值,