2x-1/2[x-1/2(x-1)]=2/3(x-1)

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2x-1/2[x-1/2(x-1)]=2/3(x-1)
2x-1/2[x-1/2(x-1)]=2/3(x-1)

2x-1/2[x-1/2(x-1)]=2/3(x-1)
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原式可写为:(2x-1)*3(x-1)=2*2[x-1/2(x-1)]
即:6(2x-1)(x-1)=4[x-1/2(x-1)]
两边同时*2(x-1)即:12(2x-1)(x-1)(x-1)=8x(x-1)-4
3(2x-1)(x-1)(x-1)=2(x*x-x-1/2)=2(x-1)(x+1/2)
3(2x-1)(x-1)=2x+1
所以,6x*x-11x+2=0,即x=.自己算去