The sum of the father's age and his son's age is 60.Eight years ago,the fater's age was 3 times that of his son.How old is each of them?

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The sum of the father's age and his son's age is 60.Eight years ago,the fater's age was 3 times that of his son.How old is each of them?
The sum of the father's age and his son's age is 60.Eight years ago,the fater's age was 3 times that of his son.How old is each of them?

The sum of the father's age and his son's age is 60.Eight years ago,the fater's age was 3 times that of his son.How old is each of them?
The father‘s age is X and the son's age is Y.
X+Y=60
(Y-8)*3=X-8
SO:X=41 Y=19
The father‘s age is 41 and the son's age is 19.

爸爸和儿子岁数和60岁，八年前爸爸是儿子岁数3倍
设今年儿子x岁，爸爸60-x岁那么八年前儿子x-8岁，爸爸60-x-8=52-x岁
52-x=3×（x-8）
解得x=19
所以儿子今年十九岁，爸爸今年41岁

The father‘s age is 41 and the son's age is 19.

x+y=60 x-8=3(y-8) x=41 y=19

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