4x+9y=12 3y-2z=1 7x+5z=19÷4

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4x+9y=12 3y-2z=1 7x+5z=19÷4
4x+9y=12 3y-2z=1 7x+5z=19÷4

4x+9y=12 3y-2z=1 7x+5z=19÷4
4x+9y=12 (1)
3y-2z=1 (2)
7x+5z=19/4 (3)
整理,(3)×4得:
28x+20z=19 (4)
消去z,(2)×10+(4)得:
28x+30y=29 (5)
消去x,(1)×7-(5)得:
33y=55
y=5/3 分别代入(1)、代入(2)得:
4x+9×5/3=12
4x+15=12
4x=-3
x=-3/4
3×5/3-2z=1
5-2z=1
2z=4
z=2
所以,方程组的解是:x=-3/4,y=5/3,z=2

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