已知m^2-n^2-6m+10n+34=0,求m+n的值 2.若a^2-2a+b^2-6b+10,求（a+b）^b

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已知m^2-n^2-6m+10n+34=0,求m+n的值 2.若a^2-2a+b^2-6b+10,求（a+b）^b
已知m^2-n^2-6m+10n+34=0,求m+n的值 2.若a^2-2a+b^2-6b+10,求（a+b）^b

已知m^2-n^2-6m+10n+34=0,求m+n的值 2.若a^2-2a+b^2-6b+10,求（a+b）^b
1).应该是m^2+n^2-6m+10n+34=0
m^2+n^2-6m+10n+34=0
(M-3)^2+(N+5)^2=0
必有M-3=0 N+5=0
==>M=3,N=-5
M+N=3-5=-2
2).应该是a^2-2a+b^2-6b+10=0
(A-1)^2+(B-3)^2=0
有A-1=0 B-3=0
A=1,B=3
(A+B)^B=(1+3)^3=64

1、由题意得m^2-6m+9+n^2+10n+25=0
(m-3)^2+(n+5)^2=0
由非负数性质可得m-3=0 ,n+5=0
所以m=3,n=-5
所以m+n=3-5=-2
2).由题意得a^2-2a+1+b^2-6b+9=0
所以(a-1)^2+(b-3)^2=0
由非负...

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1、由题意得m^2-6m+9+n^2+10n+25=0
(m-3)^2+(n+5)^2=0
由非负数性质可得m-3=0 ,n+5=0
所以m=3,n=-5
所以m+n=3-5=-2
2).由题意得a^2-2a+1+b^2-6b+9=0
所以(a-1)^2+(b-3)^2=0
由非负数性质可得a-1=0 b-3=0
所以a=1,b=3
所以（a+b）^b=(1+3)^3=64

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