作业帮chemistry problem..help pleaz!two antacids were analyzed for their cost efficiencies.antacid#1 was sold for $3.49 for 120 tablets while antacid #2 was sold for $3.99 for 150 tablets.it took 8.2ml of 0.75 M HCl to neutralize antacid #1 and it took 10.
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chemistry problem..help pleaz!two antacids were analyzed for their cost efficiencies.antacid#1 was sold for $3.49 for 120 tablets while antacid #2 was sold for $3.99 for 150 tablets.it took 8.2ml of 0.75 M HCl to neutralize antacid #1 and it took 10.
chemistry problem..help pleaz!
two antacids were analyzed for their cost efficiencies.antacid#1 was sold for $3.49 for 120 tablets while antacid #2 was sold for $3.99 for 150 tablets.it took 8.2ml of 0.75 M HCl to neutralize antacid #1 and it took 10.2ml of 0.75 M HCl to neutralize antacid #2,calculate the cost efficiency (in $/mole) of each antacid..
show the work please..thanks in advance
chemistry problem..help pleaz!two antacids were analyzed for their cost efficiencies.antacid#1 was sold for $3.49 for 120 tablets while antacid #2 was sold for $3.99 for 150 tablets.it took 8.2ml of 0.75 M HCl to neutralize antacid #1 and it took 10.
ok...let me think about it~
the solution will be:
[($3.49/120) / 0.75Mx(8.2x 10的负三次方L)]
the answer will be:#1,4.73 #2,3.48...
is that ok?负三次方我不知道怎么打~sorry about that~
希望我的答案你还满意~