【(x-y)^2+(x+y)(x-y)】÷2x.其中x=2012,y=2011.
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【(x-y)^2+(x+y)(x-y)】÷2x.其中x=2012,y=2011.
【(x-y)^2+(x+y)(x-y)】÷2x.其中x=2012,y=2011.
【(x-y)^2+(x+y)(x-y)】÷2x.其中x=2012,y=2011.
原式=(x²-2xy+y²+x²-y²)÷2x
=(2x²-2xy)÷2x
=x-y
=1
【(x-y)^2+(x+y)(x-y)】÷2x
=(x-y)(x-y+x+y)÷2x
=2x(x-y)÷2x
=x-y
=2012-2011
=1
当然是等于1啊
【1+4023】\4024=1
大括号提取同因式
上式=(x-y)(x-y+x+y)/2x
=(x-y)2x/2x
=x-y
代入x=2012,y=2011
即为1
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