解方程组3x^2-y^2=8&x^2+xy+y^2=4

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 19:07:36

解方程组3x^2-y^2=8&x^2+xy+y^2=4
解方程组3x^2-y^2=8&x^2+xy+y^2=4

解方程组3x^2-y^2=8&x^2+xy+y^2=4
x^2+xy+y^2=4
=>
2x^2+2xy+2y^2=8
联立3x^2-y^2=8
相减得
=>
x^2-2xy-3y^2=0
=>
(x-3y)(x+y)=0
=>
x=3y或x=-y
讨论:
1)x=3y
=>
3(3y)^2-y^2=8
=>
26y^2=8
=>
y=正负(根号(4/13))
x=正负3*(根号(4/13))
2)x=-y
=>
(-y)^2+(-y)*y+y^2=4
=>
y^2=4
=>
y=正负2
=>
x=负正2

∵2x²+2xy+2y²=2(x²+xy+y²)=8=3x²-y²
∴x²-2xy-3y²=(x-3y)(x+y)=0
∴x=3y或-y
再联立8=3x²-y²可得:
y=2/√13,x=6/√13 或 y=-2/√13,x=-6/√13 或 y=2,x=-2 或 y=-2,x=2