数列{an}满足a1=1 an=2a(n-1)+1(n≥2)则an等于an=2a(n-1)+1(n≥2)中的（n-1）在a的底数位置

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数列{an}满足a1=1 an=2a(n-1)+1(n≥2)则an等于an=2a(n-1)+1(n≥2)中的（n-1）在a的底数位置
数列{an}满足a1=1 an=2a(n-1)+1(n≥2)则an等于
an=2a(n-1)+1(n≥2)中的（n-1）在a的底数位置

数列{an}满足a1=1 an=2a(n-1)+1(n≥2)则an等于an=2a(n-1)+1(n≥2)中的（n-1）在a的底数位置
an=(2^n)-1

a(n)=2a(n-1)+1所以a(n)+1=2(a(n-1)+1),
令b(n)=a(n)+1,则b(n)是等比为2的等比数列
且b(1)=a(1)+1=2,
故b(n)=2*2^(n-1)=2^n,
从而a(n)=b(n)-1=2^n-1.

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