tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1不明白为什么要-1

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tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1不明白为什么要-1
tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1
tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1
从而得到:
tanA+tanB = tanA * tanB -1
不明白为什么要-1

tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1从而得到:tanA+tanB = tanA * tanB -1不明白为什么要-1
(tanA+tanB) / (1-tanA * tanB) = -1
两边同乘以 (1-tanA * tanB),等式两边就为
(tanA+tanB)= - (1-tanA * tanB),“-“(1-tanA * tanB)注意这个外面有一个负号打开括号后
(tanA+tanB)= - (1-tanA * tanB)=tanA * tanB-1

tan(A+B) = (tanA+tanB) / (1-tanA * tanB) = -1
tanA+tanB = (tanA * tanB+1)*(-1)
= tanA * tanB -1
-1是前面1和后面（-1）相乘得来的。

(tanA tanB) / (1-tanA * tanB) = -1
［ (tanA tanB) / (1-tanA * tanB) ］(1-tanA * tanB) = -1 (1-tanA * tanB)
(tanA tanB) = -1＋tanA * tanB
tanA tanB ＝tanA * tanB -1

tan(A+B)=tanA+tanB+tanAtanB? tan(A+B)-tanA-tanB/tanA*tan(A+B)等于 tan(a+b)-1/tana=2*tana 请化简! 证明 tana+tanb=tan(a+b)-tana *tanb *tan(a+b) 求证：化简[tan(A+B)-tanA-tanB]÷[tanA·tan(A+B)]=tanB.RT tan(360-a)=-tana tana+tanb=tan(a+b)-tanatanbtan(a+b)证明 tan(2a+b)=3,tan(a+b)=1,tana= tan(a+b)=2/5,tan(a-b)=1/4,求tana,tanb,tan2a tana=2/1.tan(a－B)=-5/2求.tan(B-a) , tana=2,tan(b-a)=3,则tan(b-2a) tana=0.5 tan(a-b)=-2/3求tan(b-2a) 已知tan(A-B)/tanA+sin^2C/sin^2A=1,求证：tanA×tanB＝tan^C求证tanA×tanB＝tan^2C tanA+tanB=tan(A+B)(1-tanAtanB)是什么公式? 证明tan(A+B) = (tanA+tanB)/(1-tanAtanB) tan(A+B)=(tanA+tanB)/(1-tanAtanB) 求证tan(A-B)=(tanA-tanB)/(1+tanAtanB) tan(B-A)=√3/3 tan A.tanB=1 则tanB -tanA=?