若丨2x+y-1丨+（x-2y）²=0,则x²+xy+y²的值为

若丨2x+y-1丨+（x-2y）²=0,则x²+xy+y²的值为
若丨2x+y-1丨+（x-2y）²=0,则x²+xy+y²的值为

若丨2x+y-1丨+（x-2y）²=0,则x²+xy+y²的值为
丨2x+y-1丨+（x-2y）²=0,
则2x+y-1=0且x-2y=0
解得x=0.4,y=0.2
x²+xy+y²
=0.4²+0.08+0.2²
=0.28