3x+y+17=05y-2x+17=0用代入消元法或代入加减法

用代入消元法解方程组： {y=x+1, 3x+4y=11 {x-5y=0, 3x+2y=17 {5x-3y=-1, 3x+y=5 {2x-y+5, 3x+4y=2{x+1分之三 =2y ,2(x+1)-y=11{x+y=9, 3(x+y)+2x=33 用代入消元法解方程组：{y=x+1,3x+4y=11 {x-5y=0,3x+2y=17 {5x-3y=-1,3x+y=5 {2x-y+5,3x+4y=2{x+1分之三 =2y ,2(x+1)-y=11{x+y=9,3(x+y)+2x=33 用代入消元法解二元一次方程组{x=2y① 2x+y=1② {x+y=7① 3x+y=17② {x-2y=2① 3x-4y=0②用代入消元法解二元一次方程组{x=2y① 2x+y=1②{x+y=7①3x+y=17②{x-2y=2①3x-4y=0② [(x+2y)²-（x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y²-y+17/4=0已知、x+y=6且xy=4(1)x²+y² (2)（x-y）² (3)x{四次方}+y{四次方}第一题没错 书上就这样写的！ 把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²= x-y=3 3x+2y=17 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 （x+y-5)*（x+y-5)+（x-y+3)=0 x*x-y*y 已知:3x-5y=0,求x/y,x-y/y,x-y/x 已知x、y均为实数,且满足xy+x+y=17,x^2y+y^2x=66,求x^4+x^3y+x^2*y^2+y^3x+y^4的值 已知,{3x+2y=17 2x+3y=13,则x+y= x-y= {x+y/2+x-y/3=1,3(x+y)/2+x-y/3=17 换元法解方程组3/x+y+2/x-y=17/5 2/x+y-5/x-y=1 如何求这个二元三次方程组精确解?用matlab他说没有显式解.方程：-100/x^2/y+17/40/x^3/y^2+7505627081381631/9007199254740992/x^2=0,-100/x/y^2+17/40/x^2/y^3=0我输入 clear;>> syms x y;>> [x,y]=solve('-100/x^2/y+17/40/x^3/y^2+7505 初二上学期方程题 4x+y=5 5x+4y=63x-2y=1 2x+3y=13x-2y=7 7x+5y=32x+3y=17 2x-y=-4x+5y=6 2x+y=23x-6y=4 3x+2y=52x+y=73x-4y=53x+y=1x-2y=-1x+y=42x+3y=92x-3y=74x+5y=3x+y=20004x+6y=90003x+5y=113x-2y=42x+3y=215x-2y=5x+y=54x+3y=182x+3y=16x+4y=132x+3y=40x 解x+y=17、y+2-x=-1、z+x-y=3 x'2+2x+y'2-8y+17=0,求x'y的值 x^2+2x+y^2-8y+17=0,求x^y