若|2x+y-3|+(x-1/2y)^2=0,求4x^2-2y-y^2-1的值用分组分解法

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若|2x+y-3|+(x-1/2y)^2=0,求4x^2-2y-y^2-1的值用分组分解法
若|2x+y-3|+(x-1/2y)^2=0,求4x^2-2y-y^2-1的值
用分组分解法

若|2x+y-3|+(x-1/2y)^2=0,求4x^2-2y-y^2-1的值用分组分解法
若|2x+y-3|+(x-1/2y)^2=0,则有：
2x+y-3=0且x- 1/2*y=0
即有：2x+y=3且2x-y=0
所以：
4x²-2y-y²-1
=4x²-（y²+2y+1）
=4x²-(y+1)²
=(2x+y+1)(2x-y-1)
=(3+1)*(0-1)
=4*(-1)
=-4

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