求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 00:02:23

求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa
求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa

求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa
原式=sin^2a/(sina-cosa) -(sina+cosa)/(sin^2a/cos^2a -1)
=sin^2a/(sina-cosa)-(sina+cosa)/[(sina+cosa)(sina-cosa)}/cos^2a
=sin^2a/(sina-cosa)-cos^2a/(sina-cosa)
=sina+cosa