[2(x+1)² / x²]+ [(x+1)/ x] -6=0

[2(x+1)² / x²]+ [(x+1)/ x] -6=0
[2(x+1)² / x²]+ [(x+1)/ x] -6=0

[2(x+1)² / x²]+ [(x+1)/ x] -6=0
令a=(x+1)/x
则2a²+a-6=0
(2a-3)(a+2)=0
a=3/2,a=-2
(x+1)/x=3/2
2x+2=3x
x=2
(x+1)/x=-2
x+1=-2x
x=-1/3
所以x=2,x=-1/3