先化简,再求值:12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3),其中,a=1/5,b=-5我算的-8,不对啊.

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先化简,再求值:12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3),其中,a=1/5,b=-5我算的-8,不对啊.
先化简,再求值:12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3),其中,a=1/5,b=-5
我算的-8,不对啊.

先化简,再求值:12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3),其中,a=1/5,b=-5我算的-8,不对啊.
12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3)
=12a^2b-4ab^2+5ab^2-5a^2b-2a^2b-12
=(12a^2b-5a^2b-2a^2b)+(5ab^2-4ab^2)-12
=5a^2b+ab^2-12
,其中,a=1/5,b=-5
所以
原式=5×1/5^2 ×(-5)+1/5×(-5)^2-12
=-1+5-12
=4-12
=-8

化简即是合并同类项

12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3)
=12a²b-4ab²+5ab²-5a²b-2a²b-12
=15a²b-9ab²-12
=15(1/5)²x(-5)-9x1/5x(-5)²-12
=-3-45-12
=-60

化简即是合并同类项

12(a^2b-1/3ab^2)+5(ab^2-a^2b)-4(1/2a^2b+3)
=12a²b-4ab²+5ab²-5a²b-2a²b-12
=15a²b-9ab²-12
=15(1/5)²x(-5)-9x1/5x(-5)²-12
=-3-45-12
=-60