设A=2X²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若|x-2a|+(y+3)²=0,且-2A+B=a,求A

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设A=2X²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若|x-2a|+(y+3)²=0,且-2A+B=a,求A
设A=2X²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若|x-2a|+(y+3)²=0,且-2A+B=a,求A

设A=2X²-3xy+y²-x+2y,B=4x²-6xy+2y²-3x-y,若|x-2a|+(y+3)²=0,且-2A+B=a,求A
x=2a,y=-3,-2A=-4x²+6xy-2y²+2x-4y,所以由-2A+B=a得-x-5y=a,a=5,x=10,所以A=283