(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?

来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 22:46:18

(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?

(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
解由(1+2sinxcosx+cos^2x-sin^2x)+1
=(cos^2x+sin^2x+2sinxcosx+cos^2x-sin^2x)+1
=(cos^2x+2sinxcosx+sin^2x+cos^2x-sin^2x)+1
=[(cosx+sinx)²+cos^2x-sin^2x]+1
=[(cosx+sinx)²+（cosx-sinx）（cosx+sinx）]+1
=[(cosx+sinx)（cosx+sinx+cosx-sinx）]+1

化简2*(sinxcosx-cos平方x)+1 sin^2xtanx+(cos^2x/tanx)+2sinxcosx-1+cos/sinxcosx 求证 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx 证明1-2sinxcosx/cos^2x-sin^2x=cos^2x-sin^2/1+2sinxcosx 2sin^2x-sinxcosx-cos^2=1 化简y=2sinxcosx+2cos^2x-1 化简1+2sinxcosx+2cos²x 求cos^2x-sinxcosx-1/2单调增区间 cos^2+2sinxcosx+sin^2x 化简 根号3sinXcosX+cos*2X y=sinxcosx+cos(2x)化简 化简:(cos*2x-0.5)/(sinxcosx) sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)化简 已知tanx=2,则(1)1/4sin方x-3sinxcosx/cos方x+2sinxcosx tanx=2,则1/4sin²x-3sinxcosx/cos²x+2sinxcosx=多少 y=(cos^2x)/(sinxcosx-sin^2x),(0 sin²X-sinxcosx+2cos²x=化简 化简f(x)=cos^2(x+π/12)+sinxcosx