解方程:(x^2+3x-4)^2+(2x^2-7x+6)^2=(3x^2-4x+2)^2

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解方程:(x^2+3x-4)^2+(2x^2-7x+6)^2=(3x^2-4x+2)^2
解方程:(x^2+3x-4)^2+(2x^2-7x+6)^2=(3x^2-4x+2)^2

解方程:(x^2+3x-4)^2+(2x^2-7x+6)^2=(3x^2-4x+2)^2
(x^2+3x-4)^2+(2x^2-7x+6)^2=(3x^2-4x+2)^2
(x^2+3x-4)^2=(3x^2-4x+2)^2-(2x^2-7x+6)^2
(x²+3x-4)²=[(3x²-4x+2)+(2x²-7x+6)][(3x²-4x+2)-(2x²-7x+6)]
(x²+3x-4)²=(5x²-11x+8)(x²+3x-4)
(x²+3x-4)(4x²-14x+12)=0
2(x+4)(x-1)(2x²-7x+6)=0
2(x+4)(x-1)(2x-3)(x-2)=0
x=-4 x=1 x=3/2 x=2

x+2)÷(x-1)(x+2)
=x/(x-1)
=-1/2÷(-1/2-1)
=1/2÷3/2