作业帮(x^2+y^2)(x^2+y^2+5)-36=0求x^2+y^2的值
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(x^2+y^2)(x^2+y^2+5)-36=0求x^2+y^2的值
(x^2+y^2)(x^2+y^2+5)-36=0
求x^2+y^2的值
(x^2+y^2)(x^2+y^2+5)-36=0求x^2+y^2的值
将x^2+y^2看做一个整体,设x^2+y^2=t,则t≥0
原方程等价于
t（t+5）-36=0,分解因式有
（t+9）（t-4）=0,∵t≥0,∴解得t=4
等于4
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
化简y(x+y)+(x+y)(x-y)-x^2
(x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2
5x(x-y)+2y(x-y)
化简:5(x-y)+2(x+y)-3(x-y)
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
因式分解x(x+y)(x-y)-x(x+y)^2
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
（X+2Y)(5X-2Y)
(x+2y)(5x-2y)
4x+2y-5x-y
(2x-3y)-(5x-y)
(2X-3y)-(5x-y)
(x-y)^2+5(x-y)-14
(2x-5y)(3x+y)
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+（x-3y)(x-5y)+(x-2y)(x-4y)
[(x-y)^2-(x+2y)(x-2y)]/y
(2x+y)²+(x+3y)(x-3y)-x(5x+8y)因式分解