已知x,y满足|2x-4|+﹙√3x-2y+4﹚=0求代数式[1-﹙x-y﹚/﹙x-2y﹚]÷﹙x2-y2﹚/﹙x2-4xy+4y2﹚的值

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已知x,y满足|2x-4|+﹙√3x-2y+4﹚=0求代数式[1-﹙x-y﹚/﹙x-2y﹚]÷﹙x2-y2﹚/﹙x2-4xy+4y2﹚的值
已知x,y满足|2x-4|+﹙√3x-2y+4﹚=0求代数式[1-﹙x-y﹚/﹙x-2y﹚]÷﹙x2-y2﹚/﹙x2-4xy+4y2﹚的值

已知x,y满足|2x-4|+﹙√3x-2y+4﹚=0求代数式[1-﹙x-y﹚/﹙x-2y﹚]÷﹙x2-y2﹚/﹙x2-4xy+4y2﹚的值
2x-4=0,3x-2y+4=0
x=2 ,y=5
[1-﹙x-y﹚/﹙x-2y﹚]÷﹙x2-y2﹚/﹙x2-4xy+4y2﹚
=[(x-2y-x+y)/(x-2y)][(x-2y)²/(x-y)(x+y)]
=[(-y)((x-2y)²]/[(x-y)(x+y)(x-2y)]
=[(-y)((x-2y)]/[(x-y)(x+y)]
=-5(2-10)/(-3)(7)
=-40/21

x,y满足|2x-4|+﹙√3x-2y+4﹚=0
则2x-4=0,3x-2y+4=0
所以:x=2 ,y=5
代数式
[1-﹙x-y﹚/﹙x-2y﹚]÷﹙x2-y2﹚/﹙x2-4xy+4y2﹚
=[(x-2y-x+y)/(x-2y)][(x-2y)²/(x-y)(x+y)]
=[(-y)((x-2y)²]/[(x-y)(x+y)(x-2y)]
=[(-y)((x-2y)]/[(x-y)(x+y)]
=-5(2-10)/(-3)(7)
=-40/21