(x+y-z)(z-x-y) (x-2y+2)平方-(x-2y+2)(x+2y+2)运用平方差公式和完全平方公式计算(x+y-z)(z-x-y)(x-2y+2)平方-(x-2y+2)(x+2y+2)运用平方差公式和完全平方公式计算(x+y-z)(z-x-y)和(x-2y+2)平方-(x-2y+2)(x+2y+2)
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(x+y-z)(z-x-y) (x-2y+2)平方-(x-2y+2)(x+2y+2)运用平方差公式和完全平方公式计算(x+y-z)(z-x-y)(x-2y+2)平方-(x-2y+2)(x+2y+2)运用平方差公式和完全平方公式计算(x+y-z)(z-x-y)和(x-2y+2)平方-(x-2y+2)(x+2y+2)
(x+y-z)(z-x-y) (x-2y+2)平方-(x-2y+2)(x+2y+2)
运用平方差公式和完全平方公式计算
(x+y-z)(z-x-y)
(x-2y+2)平方-(x-2y+2)(x+2y+2)
运用平方差公式和完全平方公式计算
(x+y-z)(z-x-y)和
(x-2y+2)平方-(x-2y+2)(x+2y+2)
(x+y-z)(z-x-y) (x-2y+2)平方-(x-2y+2)(x+2y+2)运用平方差公式和完全平方公式计算(x+y-z)(z-x-y)(x-2y+2)平方-(x-2y+2)(x+2y+2)运用平方差公式和完全平方公式计算(x+y-z)(z-x-y)和(x-2y+2)平方-(x-2y+2)(x+2y+2)
a(x+y-z)-b(z-x-y)-c(x-z+y)
=a(x+y-z)+b(x+y-z)-c(x+y-z)
=(a+b-c)(x+y-z)
得0
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
化简(x+Y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z)
计算题(x+y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z).
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
计算:x^2/(x-y)(x-z)+y^2/(y-x)(y-z)+z^2/(z-x)(z-y)
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答
x-y/(z-x)(z-y) 一y-z/(x-y)(x-z) +z-x/(y-z)(y-x)
x^-(y-z)^/(x+y)^-z^
计算(x+y-z)(x-y-z)
计算:(x-y+z)(-x+y+z)
(x+y-z)(x-y+z)=
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
化简:(2x-y-z)/(x-y)(x-z)+(2y-z-x)/(y-z)(y-x)+(2z-x-y)/(z-x)(z-y)化简:(2x-y-z)/(x-y)(x-z)+(2y-z-x)/(y-z)(y-x)+(2z-x-y)/(z-x)(z-y)我知道把分母化成一样的、但是之后怎么算?
x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y)x,y,z正整数 x>y>z证明 x^2x * y^2y * z^2z>x^(y+z)*y^(x+z)*z^(x+y)不是+是 *
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
化简(y-z)^2/(x-y)(x-z)+(z-x)^2/(y-x)(y-z)+(x-y)^2/(z-x)(z-y)