函数y=sin（π/4-3x）+√3cos（π/4-3x）的最小正周期为?

函数y=sin（π/4-3x）+√3cos（π/4-3x）的最小正周期为?
函数y=sin（π/4-3x）+√3cos（π/4-3x）的最小正周期为?

函数y=sin（π/4-3x）+√3cos（π/4-3x）的最小正周期为?
y=sin(π/4-3x)+√3cos(π/4-3x)=2sin(π/4-3x+π/3)=2sin(7π/12-3x)=2sin(π-7π/12+3x)
=2sin(3x+5π/12)
故T=2π/3

=2sin(π／4-3x+π／3)
=2sin(7π／12-3x)
T=π／3