(x-2y)(x+2y)(x^2+4y^2)

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(x-2y)(x+2y)(x^2+4y^2)
(x-2y)(x+2y)(x^2+4y^2)

(x-2y)(x+2y)(x^2+4y^2)
连续用平方差
(x-2y)(x+2y)(x^2+4y^2)
=(x^2+4y^2)(x^2-4y^2)
=x^4-16y^4

解
原式
=[(x-2y)(x+2y)](x²+4y²)
=(x²-4y)²(x²+4y²)
=x的4次方-16y的4次方