求不定积分∫x(x^2+1)^2dx求速打,

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求不定积分∫x(x^2+1)^2dx求速打,
求不定积分∫x(x^2+1)^2dx
求速打,

求不定积分∫x(x^2+1)^2dx求速打,
∫x(x²+1)²dx=(1/2)∫(x²+1)²d(x²+1)
=(x²+1)³/6+C

∫x(x^2+1)^2dx
=1/2∫(x^2+1)^2d(x^2+1)
=1/2· 1/3·(x^2+1)^(2+1)+c
=1/6 (x^2+1)^3+c

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