化简4x^2–9 /2x^3+3x^2+8x+12但是你们两个同时答出,,,=.= 我怎样才能把分同时给你们啊?

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化简4x^2–9 /2x^3+3x^2+8x+12但是你们两个同时答出,,,=.= 我怎样才能把分同时给你们啊?
化简4x^2–9 /2x^3+3x^2+8x+12
但是你们两个同时答出,,,=.= 我怎样才能把分同时给你们啊?

化简4x^2–9 /2x^3+3x^2+8x+12但是你们两个同时答出,,,=.= 我怎样才能把分同时给你们啊?
4x^2-9 = (2x+3)(2x-3)
2x^3+3x^2+8x+12 = x^2(2x+3)+4(2x+3) = (2x+3)(x^2+4)
约分,原式 = (2x-3)/(x^2+4)

先看分子,
4x^2–9=(2x+3)(2x-3)
在看分母,
2x^3+3x^2+8x+12=x^2(2x+3)+4(2x+3)=(2x+3)(x^2+4)
所以
4x^2–9 /2x^3+3x^2+8x+12
=(2x+3)(2x-3)/(2x+3)(x^2+4)
=2x-3/x^2+4

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