x^3-4x+3x^2-12

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x^3-4x+3x^2-12
x^3-4x+3x^2-12

x^3-4x+3x^2-12
x^3-4x+3x^2-12=x^2(x+3)-4(x+3)=(x^2-4)(x+3)=(x+2)(x-2)(x+3)

x^3-4x+3x^2-12
=(x+3)(x+2)(x-2)
零点为-3,-2,2

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