sin(π/3+α)=1/3,则cos(π/6-α)=

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sin(π/3+α)=1/3,则cos(π/6-α)=
sin(π/3+α)=1/3,则cos(π/6-α)=

sin(π/3+α)=1/3,则cos(π/6-α)=
根据诱导公式：sin（π/2－α）=cosα
得：
cos(π/6-α)
=sin[π/2-（π/6-α）]
=sin(π/3+α)
=1/3