1/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100)

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 13:46:56

1/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100)
1/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100)

1/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100)
1/(2根号1+1根号2)
=(2根号1-1根号2)/(4-2)
=根号1-(根号2)/2
1/(3根号2+2根号3)
=(3根号2-2根号3)/(18-12)
=(根号2)/2-(根号3)/3
1/(2根号1+1根号2)+1/(3根号2+2根号3)+.+1/(100根号99+99根号100)
=根号1-(根号)/2+(根号)/2-(根号3)/3+(根号)/3-...+(根号99)/99-(根号100)/100
=根号1-(根号100)/100
=1-1/10
=9/10

1/(2+根号2)=(2-根号2)/(2+根号2)*(2-根号2)
=(2-根号2)/2
=1-(根号2)/2
1/(3根号2+2根号3)=(3根号2-2根号3)/(3根号2-2根号3)*(3根号2+2根号3) =(3根号2-2根号3)/6
=(根号2)/2 -(根号3)/3

全部展开

1/(2+根号2)=(2-根号2)/(2+根号2)*(2-根号2)
=(2-根号2)/2
=1-(根号2)/2
1/(3根号2+2根号3)=(3根号2-2根号3)/(3根号2-2根号3)*(3根号2+2根号3) =(3根号2-2根号3)/6
=(根号2)/2 -(根号3)/3
同理,1/(100根号99+99根号100)=(根号99)/99 -(根号100)/100
所以, 1/(2根号1+1根号2)+1/(3根号2+2根号3)+.......+1/(100根号99+99根号100)
=[1-(根号2)/2]+[(根号2)/2-(根号3)/3]+......+[(根号99)/99 -(根号100)/100]
=1-(根号100)/100
=1-1/10=0.9

收起