(1)y=3x+2,x∈R (2)y=x²-1(x≥根号2) 请分别求出其函数的值域,

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(1)y=3x+2,x∈R (2)y=x²-1(x≥根号2) 请分别求出其函数的值域,
(1)y=3x+2,x∈R (2)y=x²-1(x≥根号2) 请分别求出其函数的值域,

(1)y=3x+2,x∈R (2)y=x²-1(x≥根号2) 请分别求出其函数的值域,
y=3x+2,x∈R
因为x∈R
所以3x∈R
所以3x+2∈R
y∈R
即值域∈R
y=x^2-1(x≥√2)
所以x^2≥2
所以x^2-1≥1
y≥1
即值域≥1

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