a+x^2=2003,b+x^2=2004,c+x^2=2005且abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c的值

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a+x^2=2003,b+x^2=2004,c+x^2=2005且abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c的值
a+x^2=2003,b+x^2=2004,c+x^2=2005且abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c的值

a+x^2=2003,b+x^2=2004,c+x^2=2005且abc=6012求a/bc+b/ca+c/ab-1/a-1/b-1/c的值
a=2003-x^2,b=2004-x^2,c=2005-x^2
所以a=b-1,c=b+1
所以a/bc+b/ca+c/ab-1/a-1/b-1/c
=a^2/(abc)+b^2/(abc)+c^2/(abc)-bc/(abc)-ac/(abc)-ca/(abc)
=(a^2+b^2+c^2-bc-ac-ca)/abc
=1/2[(a-b)^2+(a-c)^2+(b-c)^2]/abc
=1/2*[1+4+1]/(abc)
=3/6012
=1/2004