若x2+y2-2x+4y+5=0 则x= y=

若x2+y2-2x+4y+5=0 则x= y=
若x2+y2-2x+4y+5=0 则x= y=

若x2+y2-2x+4y+5=0 则x= y=
x^2-2x+1 + y^2+4y+4=0
(x-1)^2+(y+2)^2=0
x-1=0,y+2=0
x=1,y=-2

x2+y2-2x+4y+5=(x-1)^2+(y+2)^2=0
得到x=1 y=-2

x2+y2-2x+4y+5=0
(x^2-2x+1)+(y^2+4y+4)=0
(x-1)^2+(y+2)^2=0
x=1,y=-2

x2+y2-2x+4y+5=0
x^2-2x+1 + y^2+4y+4=0
(x-1)^2+(y+2)^2=0
∴x=1 y=-2
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