函数f(x)=2sin(1/2x-π/4)的周期,振幅,初相是十分钟内回答完急啊,

已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 已知函数f(x)=4sinx-2/1+sin²x 证明f(x+2π)=f(x) 函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 函数f(x)=2sin(π/4-x)×cos(π/4+x)-1化简 已知函数f(x)=sin²(π/4+x)+cos²x+1/2求最值 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π