(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)],其中x=-1,y=2.

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(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)],其中x=-1,y=2.
(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)],其中x=-1,y=2.

(2x²y-2xy²)-[(-3x²y²+3x²y)+(3x²y²-3xy²)],其中x=-1,y=2.
=2x²-2xy²+3x²y²-3x²y-3x²y²+3xy²
=-x²y+xy²
=-2-4
=-6