X-(40％X+160)/40％X+160=13/22怎么解?要详细点,有悬赏的；快点我没时间了!

x-40%x= x{x+1}{x-1}}x-2}{x-3}-40 (16x-13)/(4x-3)-(20x-24)/(4x-5)=(32x-30)/(8x-7)-(40x-43)/(8x-9)求x 十五分之七x+(160-x)=40+x 3x+16=x+40,求x 3x+16=7x-40,求x x-40%x-40%x=15 X×X+(40-X)=58 X乘以X等于40 ---------------------X=? 10x+x*x=40 (x+40%x)×85%-x=95 x+40=2x x=? 80x-多少x等于40x? (x+40%x)×85%-x=95 40x+45x 125-x 5175 4x+x=40x 40%x+70%x-x=1.8 解方程：x-60%x=240 x+20%x=24 1-25%x=十六分之三 160%x-x=9 58%x-23%x=24 40%x+70%x-x=1.8