(2007x)^2-(2007^2-1)x-1=0怎么化为(x-1)[(2007^2)x+1]=0 ?急啊

(2007x)^2-(2007^2-1)x-1=0怎么化为(x-1)[(2007^2)x+1]=0 ?急啊
(2007x)^2-(2007^2-1)x-1=0怎么化为(x-1)[(2007^2)x+1]=0 ?急啊

(2007x)^2-(2007^2-1)x-1=0怎么化为(x-1)[(2007^2)x+1]=0 ?急啊
我以a代替2007^2,a=2007^2
你的式子为ax^2-ax+x-1=0
提取公因式a,则有
ax（x-1）+（x-1）=0
再提取公因式（x-1）,则有
(ax+1)(x-1)=0
与你的式子相同