已知:loga1(b1)=loga2(b2)=……logan(bn)=x,则log(a1a2……an)(b1b2……bn)=

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已知:loga1(b1)=loga2(b2)=……logan(bn)=x,则log(a1a2……an)(b1b2……bn)=
已知:loga1(b1)=loga2(b2)=……logan(bn)=x,则log(a1a2……an)(b1b2……bn)=

已知:loga1(b1)=loga2(b2)=……logan(bn)=x,则log(a1a2……an)(b1b2……bn)=
loga1(b1)=(logb1)/(loga1);loga1(b2)=(logb2)/(loga2)=.x,依次相加为nx,相加之后等于log(a1a2……an)(b1b2……bn),因此,log(a1a2……an)(b1b2……bn)=nx