2（x+Y)^2-20(x+y)+50 和(ax+by)-2acxz-2bcyz+c^2z^2

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2（x+Y)^2-20(x+y)+50 和(ax+by)-2acxz-2bcyz+c^2z^2
2（x+Y)^2-20(x+y)+50 和(ax+by)-2acxz-2bcyz+c^2z^2

2（x+Y)^2-20(x+y)+50 和(ax+by)-2acxz-2bcyz+c^2z^2
2（x+Y)^2-20(x+y)+50
=2[(x+y)^2-10(x+y)+25]
=2(x+y-5)^2
(ax+by)^2-2acxz-2bcyz+c^2z^2
=(ax+by)^2-2cz(ax+by)+c^2z^2
=(ax+by-cz)^2

2(x+y)^2-20(x+y)+50=2(x+y+5)^2
(ax+by)-2acxz-2bcyz+c^2z^2
=(ax+by)-2cz(ax+by)+c^2z^2
=(ax+by-cz)^2

2（x+Y)^2-20(x+y)+50 =(2x+2y-10)(x+y-5)=2(x+y-5)^2
(ax+by)-2acxz-2bcyz+c^2z^2 题目你好好看看，这个分解不了！

2(X+Y-5)^2
(ax+by-cz)^2

1. 2（x+Y)^2-20(x+y)+50
=2[(x+y)^2-10(x+y)+25]
=2[(x+y)-5^2]
=2(x+y-5)^2
2. (ax+by)^2-2acxz-2bcyz+c^2z^2
=(ax+by)^2-2cz(ax+by)+c^2z^2
=(ax+by-cz)^2

2（x+Y)^2-20(x+y)+50
=2[(x+y)^2-10(x+y)+25]
=2(x+y-5)^2

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 化简y(x+y)+(x+y)(x-y)-x^2 (x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 因式分解x(x+y)(x-y)-x(x+y)^2 [(x-y)^2-(x+2y)(x-2y)]/y 计算:y-x分之x+y+x-y分之y-y-x分之2x-y x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20 {(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20 4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6 x^2(x-y)+(y-x) x(x-y)2-(y-x)3 【(x-y)^2+(x+y)(x-y)】除以 2x [(x-y)²+(x+y)(x-y)]除以2x [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简：[(x+y)(x-y)(x+y)^2-2y(x-2y)](-2y) 谢谢!