(4x+9)/5-(3+2x)/3=(x-5)/2求解

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(4x+9)/5-(3+2x)/3=(x-5)/2求解
(4x+9)/5-(3+2x)/3=(x-5)/2求解

(4x+9)/5-(3+2x)/3=(x-5)/2求解
(4x+9)/5-(3+2x)/3=(x-5)/2
两天同时乘以30
6(4x+9)-10(3+2x)=15(x-5)
24x+54-30-20x=15x-75
4x+24=15x-75
11x=99
x=9
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(4x+9)/5-(3+2x)/3=(x-5)/2
方程两边同时乘以30
6(4x+9)-10(3+2x)=15(x-5)
去括号得
24x+54-30-20x=15x-75
移项得
24x-20x-15x=30-54-75
合并同类项
-11x=-99
x=9

俩边同时乘以30 去掉分数 然后去括号 化简后得 4x+24=15x-75
然后左边是x右边是数字 得11x=99
得到答案x=9

3(4x+9)/15-5(3+2x)/15=(x-5)/2
(12x+27-15-10x)/15=(x-5)/2
(2x+12)/15=(x-5)/2
2(2x+12)=15(x-5)
4x+24=15x-75
99=11x
x=9

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