(x+2/x^2-3x+2)-(2x/x^2-3x+2)-(x+1/x^2-6x+9)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 02:47:25

(x+2/x^2-3x+2)-(2x/x^2-3x+2)-(x+1/x^2-6x+9)
(x+2/x^2-3x+2)-(2x/x^2-3x+2)-(x+1/x^2-6x+9)

(x+2/x^2-3x+2)-(2x/x^2-3x+2)-(x+1/x^2-6x+9)
原式=(x+2-2x)/(x²-3x+2)-(x+1)/(x²-6x+9)
=-(x-2)/(x-1)(x-2)-(x+1)/(x-3)²
=-1/(x-1)-(x+1)/(x-3)²
=-[(x-3)²+(x+1)(x-1)]/(x-1)(x-3)²
=-(2x²-6x+8)/(x-1)(x-3)²