设等比数列{an}的前n项的和为Sn,前n项的倒数之和为Tn,则Sn/Tn=

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 19:59:21

设等比数列{an}的前n项的和为Sn,前n项的倒数之和为Tn,则Sn/Tn=
设等比数列{an}的前n项的和为Sn,前n项的倒数之和为Tn,则Sn/Tn=

设等比数列{an}的前n项的和为Sn,前n项的倒数之和为Tn,则Sn/Tn=
设等比数列{an}首项a1,公比q,Sn=[a1(1-q^n)]/(1-q);Tn=[1/a1*(1-(1/q)^n)/(1-1/q)=(q^n-1)/[q^(n-1)*a1*(q-1)]=(q^n-1)/[an*(q-1)];Sn/Tn=a1*an