方程4/(x+3)²+2=(x-1)/(x=3)的根的个数是 ( )

方程4/(x+3)²+2=(x-1)/(x=3)的根的个数是 ( )
方程4/(x+3)²+2=(x-1)/(x=3)的根的个数是 ( )

方程4/(x+3)²+2=(x-1)/(x=3)的根的个数是 ( )
4/(x+3)²+2=(x-1)/(x+3)
方程二边同乘上(x+3)^2
4+2(x^2+6x+9)=(x-1)(x+3)=x^2+2x-3
x^2+10x+25=0
(x+5)^2=0
x=-5
故根的个数是:1