三个有理数a.b.c.满足a:b:c=2:3:5,且a²+b²+c²=abc,则a+b+c= .要通俗易懂的过程

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 04:17:17

三个有理数a.b.c.满足a:b:c=2:3:5,且a²+b²+c²=abc,则a+b+c= .要通俗易懂的过程
三个有理数a.b.c.满足a:b:c=2:3:5,且a²+b²+c²=abc,则a+b+c= .
要通俗易懂的过程

三个有理数a.b.c.满足a:b:c=2:3:5,且a²+b²+c²=abc,则a+b+c= .要通俗易懂的过程
a:b:c=2:3:5
设a=2k,b=3k,c=5k
(2k)²+(3k²)+(5k)²=2k*3k*5k
38k²=30k³
38=30k
k=38/30
a+b+c
=2k+3k+5k
=10k
=10*(38/30)
=38/3

a=2x
b=3x
c=5x
得38x^2=30x^3
x=19/15
a+b+c=190/15

a:b:c=2:3:5
则令a=2x,b=3x,c=5x
所以4x²+9x²+25x²=30x³
x=19/15
所以a+b+c=10x=38/3

令abc为2k.3k.5k
则4k*2+9k*2+25k*2=30k*3
38k*2=30k*3
K=19/15
10k=38/3
则答案为38/3

a:b:c=2:3:5
设:a=2R,b=3R,c=5R (R为正整数) {代入 a²+b²+c²=abc中}
得: (2R)²+(3R)²+(5R)²= 2R x 3R x 5R
4R²+9R²+25R² = 30R³
...

全部展开

a:b:c=2:3:5
设:a=2R,b=3R,c=5R (R为正整数) {代入 a²+b²+c²=abc中}
得: (2R)²+(3R)²+(5R)²= 2R x 3R x 5R
4R²+9R²+25R² = 30R³
38R² = 30R³
19 = 15R
R =19/15
a+b+c= 2R +3R+5R
=R(2+3+5)
=10R
= 10 x 19/15 {代入R的值}
= 38/3
则a+b+c= 38/3

收起

a:b:c=2:3:5
b=3a/2,c=5a/2
a²+b²+c²=abc
a²+9a²/4+25a²/4=15a³/4
38a²=15a³
a²(15a-38)=0
a=0或38/15
a=0时,b=0, c=0, a+b+c=0
a=38/15时,b=19/5, c=19/3, a+b+c= (38+19*3+19*5)/15=190/15=38/3