1,(X/3)/12+(2X/3)/30+1/2=(3X/5)/12+(2X/5)/302,(S×1/3)/12+(S×2/3)/30+1/2=(S×3/5)/12+(S×2/5)/30

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 13:44:14

1,(X/3)/12+(2X/3)/30+1/2=(3X/5)/12+(2X/5)/302,(S×1/3)/12+(S×2/3)/30+1/2=(S×3/5)/12+(S×2/5)/30
1,(X/3)/12+(2X/3)/30+1/2=(3X/5)/12+(2X/5)/30
2,(S×1/3)/12+(S×2/3)/30+1/2=(S×3/5)/12+(S×2/5)/30

1,(X/3)/12+(2X/3)/30+1/2=(3X/5)/12+(2X/5)/302,(S×1/3)/12+(S×2/3)/30+1/2=(S×3/5)/12+(S×2/5)/30
(X/3)/12+(2X/3)/30+1/2=(3X/5)/12+(2X/5)/30
x/36+x/45+1/2=x/20+x/75
1/2=x/20+x/75- x/36-x/45=x/75
所以:x=75/2

30

移项得 1/2 = (3/5 - 1/3)x/12 +x/30(2/5 - 2/3) 注意到3/5 - 1/3=2/5 -2/3= 4/15
合并得x=175/4

x^3+x-30(分解因式);x^12-y^12;x^15+x^14+x^13.x^2+x+1 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了 想不起来怎么算了 想知道 X值是多少 计算:x^2-3x-1/x-1 - x^2+3x+3/x+3 + 2x+12/x+3 求x^2-3x/x^2-6x+9*x^2-11x+30/x^2-5x-1 (x^21+x^15+x^12+x^9+x^6+x^3+1)/(x^2+x+1) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程 x{x+1}{x-1}}x-2}{x-3}-40 |x+1|-|x|+|x-2|-|-x+3|已知x+2 x^5-x^4+x^3-x^2+x-1 (X+1)X(X+2)X(X+3)=504 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 数学题化简2(x-3)(x+3)-(x+3)(3-x)其中x=12(x-3)(x+3)-(x+3)(3-x) 其中x=1 化简:[√(x^2-6x+9)/x^2-x-12]*(x^3-16x)/(x^2-3x)-1/(x+3) {x>3} 化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x)