y=ax^2+bx^2+c =a(x^2+b/a*x)+c =a[x^2+2*(b/2a)x+(b/2a)^2-(b/2a)^2]+c =a(x+b/2a)^2+c-a*(b/2a)^2=a(x+b/2a)^2+(4ac-b^2)/4a做到第3步这一步=a(x+b/2a)^2+c-a*(b/2a)^2,c-a*(b/2a)^2怎么化为(4ac-b^2)/4a的?

来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 00:43:42

y=ax^2+bx^2+c =a(x^2+b/a*x)+c =a[x^2+2*(b/2a)x+(b/2a)^2-(b/2a)^2]+c =a(x+b/2a)^2+c-a*(b/2a)^2=a(x+b/2a)^2+(4ac-b^2)/4a做到第3步这一步=a(x+b/2a)^2+c-a*(b/2a)^2,c-a*(b/2a)^2怎么化为(4ac-b^2)/4a的?
y=ax^2+bx^2+c
=a(x^2+b/a*x)+c
=a[x^2+2*(b/2a)x+(b/2a)^2-(b/2a)^2]+c
=a(x+b/2a)^2+c-a*(b/2a)^2
=a(x+b/2a)^2+(4ac-b^2)/4a
做到第3步这一步=a(x+b/2a)^2+c-a*(b/2a)^2,
c-a*(b/2a)^2怎么化为(4ac-b^2)/4a的?

y=ax^2+bx^2+c =a(x^2+b/a*x)+c =a[x^2+2*(b/2a)x+(b/2a)^2-(b/2a)^2]+c =a(x+b/2a)^2+c-a*(b/2a)^2=a(x+b/2a)^2+(4ac-b^2)/4a做到第3步这一步=a(x+b/2a)^2+c-a*(b/2a)^2,c-a*(b/2a)^2怎么化为(4ac-b^2)/4a的?
c-a*(b/2a)^2
=c-a*b²/(4a²)
=c-b²/(4a)
=4ac/(4a)-b²/(4a)
=(4ac-b²)/(4a)

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