2.已知两条直线a1x+b1x=c1和a2x+b2x=c2,当a1/a2≠b1/b2时,方程组ax+b1x=c1;a2x+b2x=c2有唯一...

2.已知两条直线a1x+b1x=c1和a2x+b2x=c2,当a1/a2≠b1/b2时,方程组ax+b1x=c1;a2x+b2x=c2有唯一...
2.已知两条直线a1x+b1x=c1和a2x+b2x=c2,当a1/a2≠b1/b2时,方程组a
x+b1x=c1;a2x+b2x=c2有唯一...

2.已知两条直线a1x+b1x=c1和a2x+b2x=c2,当a1/a2≠b1/b2时,方程组ax+b1x=c1;a2x+b2x=c2有唯一...
y2与x轴的两交点,是指 y2=0 即a2x2+b2x+c2=0的两根
此时a1/a2=b1/b2=c1/c2=k
所以
y1=a1x2+b1x+c1＝k(a2x2+b2x+c2)=k*0=0
所以,y1和y2与X轴的交点是相同的　两交点间距离均为d