(5X+1-Y)+(5X+1-Y-Z)+(5X+1-Y-Z-A)+(5X+1-Y-Z-A-B)=5X+1 /////x=几

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 20:46:45

(5X+1-Y)+(5X+1-Y-Z)+(5X+1-Y-Z-A)+(5X+1-Y-Z-A-B)=5X+1 /////x=几
(5X+1-Y)+(5X+1-Y-Z)+(5X+1-Y-Z-A)+(5X+1-Y-Z-A-B)=5X+1 /////x=几

(5X+1-Y)+(5X+1-Y-Z)+(5X+1-Y-Z-A)+(5X+1-Y-Z-A-B)=5X+1 /////x=几
(5X+1-Y)+(5X+1-Y-Z)+(5X+1-Y-Z-A)+(5X+1-Y-Z-A-B)=5X+1
20X+4-4Y-3Z-2A-B=5X+1
15X=1-4+4Y+3Z+2A+B
=4Y+3Z+2A+B-3
X=(4Y+3Z+2A+B-3)/15

X=(4Y+3Z+2A+B-3)/15

已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z. 已知3x=4Y,5Y=6Z,求 (1)x:y:z;(2)x+y/y+z.请说明道理, (3x+2y-5z+1)(-3x+2y-5z-1) {x+y-z=11 y+z-x=5 z+x-y=1 {x+y-z=11,x-y-z=-5,x-y+z=1 x²-y²+5x+3y+4(x+y-2xy)(x+y-z)+(xy-1)² (1)已知3x=2y=z,求2x+y-z分之x-y+2z的值.(2)若(x+y):(3x-2y)=5:2,则x:y=? x+y+z=651 (1+10%)x=y (1+5%)y=z 解这个方程组x+y+z=651 (1+10%)x=y(1+5%)y=z是这样 已知实数X.Y.Z满足(Y+Z)分之X+(Z+X)分之Y+(X+Y)分之Z=1,则(Y+Z)分之X平方+(Z+X)分之Y平方+(X+Y)分之Z平方的值为( ) (1)x/2+y/3=-1 ,x/3+z/4=4 ,y/2+z/4=-4(2)x:y=4:7 ,x:z=3:5 ,x-2y+3z=30(3)x+3y-z=13 ,3x-2y-z=2 ,2x-y+z=-3 (1)x:y:z=3:2:5,2x+3y+8=5 (2)5x-3y+z=5,4x+3y-2z=9x-5y-z=-17 两道三元一次方程题(要有步骤)1.x+y=3,y+z=6,z+x=72.x-2y=4,3x-3y-2z=1,x+y+z=5 解三元一次方程组.速回.(1)X+Y+Z=25 X-Y=1 2X+Y-Z=18(2)X-Y-Z=0 X+Y-3Z=4 2X+3Y-5Z=14(3) X-2Y=-9 Y-Z=3 2Z+x=47(4)3X-y+z=4 2X+3Y-Z=12 X+Y+z=-28(5)4X+9Y=13 3y-2Z=-1 7X+5Z=17速回 我会奖励积分 解方程组 2x+3y-z=5 x-2y+2z=6 3x-y-3z=7{ 2x+3y-z=5 (1) { x-2y+2z=6 (2){ 3x-y-3z=7 (3)x=?y=?z=? 分解因式 4a(x-y)²-a²(y-x)³ (x+y+z)(x-y+z)+(y-x+z) (y-x-z)(1)4a(x-y)²-a²(y-x)³ (2)(x+y+z)(x-y+z)+(y-x+z) (y-x-z) 已知3X=5Y ,4Y=5Z,求:(1) Y与Z的比值 (2) x:y:z 问5道3元一次方程组题目(1) y=2x-7{ 5x+3y+2z=23x-4z=4 (2) 4x+9y=12{3y-2z=17x+5z=19/4(3)4x-9z=17{3x+y+5z=18x+2y+3z=2(4) 2x+4y+3z=9{3x-2y+5z=115x-6y+7z=13(5) x:y=3:2{y:z=5:4x+y+z=66 解下列方程组 (1)x=5 x+5-2z=-4 4x-3y+2z=1(2)9x-5y+z=-6 9x+y+4z=3 -9x+3y-5z(3)x+y=22 x+z=-27 y+z=13